a3 b3 c3-3abc=(a b c)(a2 b2 c2-ab-bc-ca)
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proof a3 b3 c3-3abc=(a b c)(a2 b2 c2-ab-bc-ac)
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a3 b3 c3 - 3abc = ( a b c).(a2 b2 c2 - ab - bc - ca)
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mathematics solution "a b c=15, a² b² c²=83, ab bc ca=?"
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a³ b³ c³-3abc=(a b c)(a² b² c²-ab-bc-ca)=1/2(a b c){(a-b)² (b-c)² (c-a)²]
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質問への返答 因数分解 a^3 b^3 c^3-3abc
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if a b c = 9 and ab bc ca = 18, then what is the value of a3 b3 c3 – 3abc ?
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to prove a3 b3 c3 - 3abc = (a b c)(a2 b2 c2 - ab - bc - ac) class 9th
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यदि a^(3) b^(3) c^(3) - 3abc = p(a^(2) b^(2) c^(2) - ab - bc - ca) तो p का मान लिखिए। |...
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show that (a b c)[a^2 b^2 c^2-ab-bc-ca] = a^3 b^3 c^3-3abc || verify identity | #mathsclass9 |
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(18) if a b c = 8 and ab bc ca = 20 find a^3 b^3 c^3 - 3abc #fapavte || polynomial
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if a b c=9 and ab bc ca=23 then a³ b³ c³-3abc=? #class9 #polynomial
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#mitra#maths prove that a3 b3 c3-3abc= (a b c)(a2 b2 c2-ab-bc-ca)=1/2(a b c)(a-b)2 (b-c)2 (c-a)2
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prove : `a^3 b^3 c^3-3abc = 1/2(a b c){(a-b)^2 (b-c)^2 (c-a)^2}`