binomial theorem: prove that c0/1 c1/2 c2/3 ......... cn/(n 1)=[2^(n 1)-1]/(n 1).
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![show that c0 c1 / 2 c2 / 3 ... cn / (n 1) = { [2 raised to power n 1] - 1 } / (n 1).](https://i.ytimg.com/vi/cvClBZoht6A/mqdefault.jpg)
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show that c0 c1 / 2 c2 / 3 ... cn / (n 1) = { [2 raised to power n 1] - 1 } / (n 1).
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