double integrals: find ∫∫r y/x da,where r is the region in the first quadrant x^2 y^2=1 ; x^2 y^2=4
Published 2 years ago • 5.1K plays • Length 8:05
Download video MP4
Download video MP3
Similar videos
-
6:46
calculus help: double integrals: ∫∫(2-x^2)da, where r is the region bounded by y=1 x^2 and y=9-x^2
-
5:33
calculus: evaluate the double integral ∫∫_r(3x-y) da ,where r is the region in the first quadrant
-
6:14
calculus help: double integrals: compute ∫∫ xy da, where r is the region enclosed by y=√x,y=6-x, y=0
-
4:29
calculus help: double integrals: ∬d xy da where d = {(x, y) |0 ≤ y ≤ 1, y² ≤ x ≤ y 2);
-
15:29
double and triple integrals
-
9:44
evaluation of double integrals over a region.
-
7:14
how to change the order of a double integral (from dydx to dxdy)
-
6:53
calculus help: first quadrant inside the circle x^2 y^2 = 2 and outside the circle x^2 y^2 = 1
-
4:34
calculus help: double integrals - ∫∫ √(x^2 y^2 ) dydx - polar coordinates - techniques
-
8:00
calculus help: double integrals: polar coordinates 1/√(y^2 x^2 ) dxdy ,d={(x,y)/y ,y≥x,2≤x^2 y^2≤10}
-
5:40
let f(x) be a continuous function f(2)=-1,f(5)=2,f'(2)=8,and f'(5)=5. (f(x))^3 f'(x) √((f(x))^2 1)dx
-
25:02
double integrals
-
0:35
how real men integrate functions
-
4:44
calculus: double integrals: if we change the order of integration we obtain the sum of two integrals
-
5:34
calculus help: double integrals: 1/(1 x^2 y^2 ) dydx - polar coordinates
-
10:45
calculus help: double integrals: y^2/(x^2 y^2 ) dydx - integration by trigonometric substitution
-
3:13
calculus help: double integrals: xy sin(xy^2 ) dydx - integration by substitution
-
2:36
calculus help: integral of ∫ 15x(x 4)^(3/2) dx - integration by parts
-
2:04
calculus help: integral of (1-x x^2-x^3 x^4-x^5 ⋯)/(1 x x^2 x^3 x^4 x^5 ⋯) series - hard high school
-
4:14
calculus help: integrating factor - y' 3x^2 y= x^2 - linear differential equations
Clip.africa.com - Privacy-policy