∫arccos(√x)/√(x(1-x)) dx [0, 1]. solve integral without using substitution method.

Published 1 year ago • 258 plays • Length 4:09

Download video MP4
Download video MP3

Similar videos

0:43

∫arctan(√x)) dx = ?? mit integration bee 2024, regular season, problem 8. #mitintegrationbee
$∫x⁸/(x¹² 1) dx [0, ∞]. solve integral without partial fractions and substitution.$ 3:45

∫x⁸/(x¹² 1) dx [0, ∞]. solve integral without partial fractions and substitution.
0:59

∫x²⁰²²/(x 1)²⁰²⁴ dx [0, ∞] = ? what is the easier way to solve this problem?
2:23

∫arctan(e^(tan(x))) dx [0, 2π] = ?
0:42

∫(sin⁶(x) cos⁶(x) 3sin²(x)cos²(x)) dx. mit integration bee 2023, qualifying exam, question 12.
4:14

(∫_0^1 (1 - x²)²⁰²³ dx)/(∫_0^1 (1 - x²)²⁰²⁴ dx). solve by recursive formula & integration by parts.
2:27

∫tan⁻¹(e⁻ˣ) dx [-1, 1]. interesting definite integral question but with surprisingly simple answer.
3:17

i will derive!
$integral of 1/(1 x^4) by brute-force partial fraction!$ 18:13

integral of 1/(1 x^4) by brute-force partial fraction!
11:27

integral of ln(x) from 0 to 1
6:35

∫(x-1)/((x 1)ln(x)) dx [0, 1]. solving by double integrals, geometric series & wallis product for π.
9:49

deriving recursive formula for solving integral sin^n (x) dx [0, π], find the answer for n = 9.
$∫1/(x⁴ 1) dx [0, ∞]. can we solve this integral without using partial fraction?$ 4:09

∫1/(x⁴ 1) dx [0, ∞]. can we solve this integral without using partial fraction?
3:45

∫arctan((1 - 2x)/(1 x - x²)) dx [0, 1]. solve integral of inverse tangent using substitution.
5:22

solving a quartic equation using solution for quadratic equation.
1:37

∫arctan(1/x) dx = ??

Clip.africa.com - Privacy-policy