if `a b c=0` then prove that `a^3 b^3 c^3=3 abc`

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$if `3x=a b c ,` then the value of `(x-a)^3 \ (x-b)^3 \ (x-c)^3-3\ (x-a)(x-b)(x-c)` is (a)`a b$ 2:30

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