if a b c=6 and ab bc ca=11 find a^3 b^3 c^3-3abc

Published 1 year ago • 6.1K plays • Length 3:45

Download video MP4
Download video MP3

Similar videos

6:23

(a b c)³-a³-b³-c³=3(a b)(b c)(c a) a b c whole cube-a3-b3-c3 prove(a b c)3−a3−b3−c3=3(a b)(b c)(c a)
3:36

https://www.youtube.com/@bàďèśť211
1:44

q97 | if (a b)/c=(b c)/a=(c a)/b=k then k is equal to | ratio and proportion | gravity coaching
2:11

if a b c = 9 and ab bc ca = 18, then what is the value of a3 b3 c3 – 3abc ?
4:25

prove that (a b c)^3 - a^3-b^3-c^3 = 3(a b)(b c)(c a). | 9 | polynomials | maths | ncert exempla...
1:01

menyala abang kuh ib:@cessa.m.v #sakuraschoolsimulator #sakurass #sakurass
6:43

video #13 shortcut trick to combine two/three different ratios- (very important for ibps-po/clerk)
5:13

if a b c=0 then prove that a³ b³ c³=3abc ! easy step-by-step explanation! maths concept!
7:50

if a b c = 14 and a^3 b^3 c^3 a b c=98 find the value of ab bc ca
7:35

prove that ab/c^3 bc/a^3 ca/b^3 greater1/a 1/b 1/c, where a,b,c are different positive real
2:01

c | math '(a)^3 (b)^3 (c)^3-3abc' | codelearning
$prove : `a^3 b^3 c^3-3abc = 1/2(a b c){(a-b)^2 (b-c)^2 (c-a)^2}`$ 4:21

prove : `a^3 b^3 c^3-3abc = 1/2(a b c){(a-b)^2 (b-c)^2 (c-a)^2}`
3:07

यदि a^(3) b^(3) c^(3) - 3abc = p(a^(2) b^(2) c^(2) - ab - bc - ca) तो p का मान लिखिए। |...
4:00

a3 b3 c3 - 3abc = ( a b c).(a2 b2 c2 - ab - bc - ca)
1:48

if cos(a b)=½ , tan(a-b)=1/[√3], find the value of sec(2a-3b), if (a b) is an acute angle
10:35

prove that (a b c)³ - a³ - b³ - c³ = 3(a b)(b c)(c a)
2:18

if `a b c=0` then prove that `a^3 b^3 c^3=3 abc`
1:19

(a-b)^3 (b-c)^3 (c-a)^3/9(a-b)(b-c)(c-a) =? simplification tnpsc previous year question 2022
2:42

c | math '(a^3 b^3 c^3)-3abc #2' | codelearning
3:21

if `a b c=6` and `ab bc ca=11` is given then find the value of `a^3 b^3 c^3-3abc`

Clip.africa.com - Privacy-policy