the differential coefficient of tan ^1(sin x cos x/cos x-sin x) w.r.t. x is : iv (a) 0 (b) 1/2 (d...
Published 2 years ago • 171 plays • Length 2:34Download video MP4
Download video MP3
Similar videos
-
6:06
if y = tan⁻¹(cosx sinx / cosx - sinx) then find dy/dx
-
2:24
q5 | write in the simplest form:- tan^(-1)((cosx-sinx)/(cosx sinx)) | inverse trigonometric fun
-
![differentiate tan^-1[(sin(x) -cos(x)) /(sin(x) cos(x) ) ] by x/2](https://i.ytimg.com/vi/eZFewINhuTg/mqdefault.jpg)
3:19
differentiate tan^-1[(sin(x) -cos(x)) /(sin(x) cos(x) ) ] by x/2
-
5:46
differentiate cot⁻¹(cosx - sinx/cosx sinx)
-
4:55
the derivative of `tan^(-1)((sin x - cos x)/(sin x cos x))`, with respect to ` x/2`, where
-
3:07
express in the simplest form `tan^(-1) ((cos x-sinx)/(cosx sin x))`
-
5:41
differentiation : using the formulae book e^x, ln x, sin x, cos x, tan x : examsolutions
-
6:38:13
100 calculus derivatives (ultimate derivative tutorial)
-
12:18
a beautiful result in calculus: solution using feynman integration ( integral cos(x)/(x^2 1) )
-
3:08
visual calculus: derivative of sin(θ) is cos(θ)
-
0:16
#trigonometry all formulas
-
5:04
verify trig identity (cos x sin x)/(cos x - sin x) - ( cos x - sin x)/(cos x sin x) = 2 tan (2x)
-
10:33
differentiate tan^-1((1 cosx)/sinx)) then dy/dx / tan inverse((1 cosx)/sinx)) / differentiation
-
![if y=tan^(-1) [(1-cosx)/sinx] find dy/dx if y = tan^(-1)[cosx/(1-sinx)] find dy/dx differential](https://i.ytimg.com/vi/MQR3qsJpJnI/mqdefault.jpg)
11:53
if y=tan^(-1) [(1-cosx)/sinx] find dy/dx if y = tan^(-1)[cosx/(1-sinx)] find dy/dx differential
-
0:51
prove (1 - sin x)/cos x = cos x / 1 sin x
-
![find the derivative of `tan^(- 1)[(cosx)/(1 sinx)]` wrt `x`](https://i.ytimg.com/vi/0bKKxKBhoUM/mqdefault.jpg)
3:17
find the derivative of `tan^(- 1)[(cosx)/(1 sinx)]` wrt `x`
-
6:19
verify trig identity cos x/(1- tan x) sin x/(1 - cot x) = sin x cos x. common denominator
-
1:01
find the derivative of y = tan x = sin x / cos x
-
2:04
integral of (sin(x) - cos(x))/(sin(x) cos(x)) (substitution)
-
2:40
q13 | differentiate tan^(-1)(cosx/(1 sinx ))
-
8:40
y= (sinx - cosx)^sinx - cosx / differentiate y=(sinx - cosx)^sinx - cosx / sinx-cosx power sinx-cosx
-
17:08
establishing the derivatives of sin x, cos x & tan x